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3+(2/5)b=11(-2/3)b
We move all terms to the left:
3+(2/5)b-(11(-2/3)b)=0
Domain of the equation: 5)b!=0
b!=0/1
b!=0
b∈R
Domain of the equation: 3)b)!=0We add all the numbers together, and all the variables
b!=0/1
b!=0
b∈R
(+2/5)b-(11(-2/3)b)+3=0
We multiply parentheses
2b^2-(11(-2/3)b)+3=0
We multiply all the terms by the denominator
2b^2*3)b)-(11(+3*3)b)-2=0
We add all the numbers together, and all the variables
2b^2*3)b)-(119b)-2=0
We add all the numbers together, and all the variables
2b^2*3)b)-119b-2=0
Wy multiply elements
6b^3=0
We do not support ebpression: b^3
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