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3+(2x+3)=5(x-5)
We move all terms to the left:
3+(2x+3)-(5(x-5))=0
We get rid of parentheses
2x-(5(x-5))+3+3=0
We calculate terms in parentheses: -(5(x-5)), so:We add all the numbers together, and all the variables
5(x-5)
We multiply parentheses
5x-25
Back to the equation:
-(5x-25)
2x-(5x-25)+6=0
We get rid of parentheses
2x-5x+25+6=0
We add all the numbers together, and all the variables
-3x+31=0
We move all terms containing x to the left, all other terms to the right
-3x=-31
x=-31/-3
x=10+1/3
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