3+(2z+4)=6(5z+2)

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Solution for 3+(2z+4)=6(5z+2) equation: 



3+(2z+4)=6(5z+2)

We move all terms to the left:

3+(2z+4)-(6(5z+2))=0

We get rid of parentheses

2z-(6(5z+2))+4+3=0



We calculate terms in parentheses: -(6(5z+2)), so:

6(5z+2)

We multiply parentheses

30z+12

Back to the equation:

-(30z+12)



We add all the numbers together, and all the variables

2z-(30z+12)+7=0

We get rid of parentheses

2z-30z-12+7=0

We add all the numbers together, and all the variables

-28z-5=0

We move all terms containing z to the left, all other terms to the right

-28z=5

z=5/-28

z=-5/28

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