3+(3+2)4+100=z

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Solution for 3+(3+2)4+100=z equation: 



3+(3+2)4+100=z

We move all terms to the left:

3+(3+2)4+100-(z)=0

We add all the numbers together, and all the variables

-z+3+100+54=0

We add all the numbers together, and all the variables

-1z+157=0

We move all terms containing z to the left, all other terms to the right

-z=-157

z=-157/-1

z=+157

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