3+(3d-2)=19

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Solution for 3+(3d-2)=19 equation: 



3+(3d-2)=19

We move all terms to the left:

3+(3d-2)-(19)=0

We add all the numbers together, and all the variables

(3d-2)-16=0

We get rid of parentheses

3d-2-16=0

We add all the numbers together, and all the variables

3d-18=0

We move all terms containing d to the left, all other terms to the right

3d=18

d=18/3

d=6

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