3+(b+3)-4(-2+b)=19

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Solution for 3+(b+3)-4(-2+b)=19 equation: 



3+(b+3)-4(-2+b)=19

We move all terms to the left:

3+(b+3)-4(-2+b)-(19)=0

We add all the numbers together, and all the variables

(b+3)-4(b-2)+3-19=0

We add all the numbers together, and all the variables

(b+3)-4(b-2)-16=0

We multiply parentheses

(b+3)-4b+8-16=0

We get rid of parentheses

b-4b+3+8-16=0

We add all the numbers together, and all the variables

-3b-5=0

We move all terms containing b to the left, all other terms to the right

-3b=5

b=5/-3

b=-1+2/3

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