3+(b+8)=3+(b+8)=3+(8+b)

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Solution for 3+(b+8)=3+(b+8)=3+(8+b) equation: 



3+(b+8)=3+(b+8)=3+(8+b)

We move all terms to the left:

3+(b+8)-(3+(b+8))=0

We get rid of parentheses

b-(3+(b+8))+8+3=0



We calculate terms in parentheses: -(3+(b+8)), so:

3+(b+8)

determiningTheFunctionDomain
(b+8)+3

We get rid of parentheses

b+8+3

We add all the numbers together, and all the variables

b+11

Back to the equation:

-(b+11)



We add all the numbers together, and all the variables

b-(b+11)+11=0

We get rid of parentheses

b-b-11+11=0

We add all the numbers together, and all the variables

=0

b=0/1

b=0

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