3+(q+4)2=15

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Solution for 3+(q+4)2=15 equation: 



3+(q+4)2=15

We move all terms to the left:

3+(q+4)2-(15)=0

We add all the numbers together, and all the variables

(q+4)2-12=0

We multiply parentheses

2q+8-12=0

We add all the numbers together, and all the variables

2q-4=0

We move all terms containing q to the left, all other terms to the right

2q=4

q=4/2

q=2

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