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3+(x+1)=4-(4x-3)
We move all terms to the left:
3+(x+1)-(4-(4x-3))=0
We get rid of parentheses
x-(4-(4x-3))+1+3=0
We calculate terms in parentheses: -(4-(4x-3)), so:We add all the numbers together, and all the variables
4-(4x-3)
determiningTheFunctionDomain -(4x-3)+4
We get rid of parentheses
-4x+3+4
We add all the numbers together, and all the variables
-4x+7
Back to the equation:
-(-4x+7)
x-(-4x+7)+4=0
We get rid of parentheses
x+4x-7+4=0
We add all the numbers together, and all the variables
5x-3=0
We move all terms containing x to the left, all other terms to the right
5x=3
x=3/5
x=3/5
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