3+(y-1)=(y+1)

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Solution for 3+(y-1)=(y+1) equation: 



3+(y-1)=(y+1)

We move all terms to the left:

3+(y-1)-((y+1))=0

We get rid of parentheses

y-((y+1))-1+3=0



We calculate terms in parentheses: -((y+1)), so:

(y+1)

We get rid of parentheses

y+1

Back to the equation:

-(y+1)



We add all the numbers together, and all the variables

y-(y+1)+2=0

We get rid of parentheses

y-y-1+2=0

We add all the numbers together, and all the variables

1!=0

There is no solution for this equation

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