3+(y-1)=2(y+1)

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Solution for 3+(y-1)=2(y+1) equation: 



3+(y-1)=2(y+1)

We move all terms to the left:

3+(y-1)-(2(y+1))=0

We get rid of parentheses

y-(2(y+1))-1+3=0



We calculate terms in parentheses: -(2(y+1)), so:

2(y+1)

We multiply parentheses

2y+2

Back to the equation:

-(2y+2)



We add all the numbers together, and all the variables

y-(2y+2)+2=0

We get rid of parentheses

y-2y-2+2=0

We add all the numbers together, and all the variables

-y=0

y=0/-1

y=0

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