3+0,4x=1000/x+3+0.2x

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Solution for 3+0,4x=1000/x+3+0.2x equation:


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

0.4*x+3 = 0.2*x+1000/x+3 // - 0.2*x+1000/x+3

0.4*x-(0.2*x)-(1000/x)-3+3 = 0

0.4*x-0.2*x-1000*x^-1-3+3 = 0

0.2*x-1000*x^-1 = 0

x^-1*(0.2*x^2-1000) = 0

0.2*x^2 = 1000 // : 0.2

x^2 = 5000

x^2 = 5000 // ^ 1/2

abs(x) = 50*2^(1/2)

x = 50*2^(1/2) or x = -(50*2^(1/2))

1/x = 0

1*x^-1 = 0 // : 1

x^-1 = 0

x naleu017Cy do O

x in { 50*2^(1/2), -(50*2^(1/2)) }

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