3+1/4(t+2)=3.5t-4

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Solution for 3+1/4(t+2)=3.5t-4 equation: 



3+1/4(t+2)=3.5t-4

We move all terms to the left:

3+1/4(t+2)-(3.5t-4)=0



Domain of the equation: 4(t+2)!=0

t∈R



We get rid of parentheses

1/4(t+2)-3.5t+4+3=0

We multiply all the terms by the denominator


-(3.5t)*4(t+2)+4*4(t+2)+3*4(t+2)+1=0

We add all the numbers together, and all the variables

-(+3.5t)*4(t+2)+4*4(t+2)+3*4(t+2)+1=0

Wy multiply elements

-(+3.5t)*4(t+2)+16t(t+12t(t+1=0

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