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3+1/4(x-4)=2/5(2+3x)
We move all terms to the left:
3+1/4(x-4)-(2/5(2+3x))=0
Domain of the equation: 4(x-4)!=0
x∈R
Domain of the equation: 5(2+3x))!=0We add all the numbers together, and all the variables
x∈R
1/4(x-4)-(2/5(3x+2))+3=0
We calculate fractions
(5x3/(4(x-4)*5(3x+2)))+(-8xx/(4(x-4)*5(3x+2)))+3=0
We calculate terms in parentheses: +(5x3/(4(x-4)*5(3x+2))), so:
5x3/(4(x-4)*5(3x+2))
We multiply all the terms by the denominator
5x3
We add all the numbers together, and all the variables
5x^3
We do not support expression: x^3
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