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3+1/5b=19
We move all terms to the left:
3+1/5b-(19)=0
Domain of the equation: 5b!=0We add all the numbers together, and all the variables
b!=0/5
b!=0
b∈R
1/5b-16=0
We multiply all the terms by the denominator
-16*5b+1=0
Wy multiply elements
-80b+1=0
We move all terms containing b to the left, all other terms to the right
-80b=-1
b=-1/-80
b=1/80
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