3+1/7(21a+14)=2(3a+9)+2

Simple and best practice solution for 3+1/7(21a+14)=2(3a+9)+2 equation. Check how easy it is, and learn it for the future. Our solution is simple, and easy to understand, so don`t hesitate to use it as a solution of your homework.

If it's not what You are looking for type in the equation solver your own equation and let us solve it.

Solution for 3+1/7(21a+14)=2(3a+9)+2 equation: 



3+1/7(21a+14)=2(3a+9)+2

We move all terms to the left:

3+1/7(21a+14)-(2(3a+9)+2)=0



Domain of the equation: 7(21a+14)!=0

a∈R



We multiply all the terms by the denominator


-((2(3a+9)+2))*7(21a+14)+3*7(21a+14)+1=0



We calculate terms in parentheses: -((2(3a+9)+2))*7(21a+14), so:

(2(3a+9)+2))*7(21a+14



Wy multiply elements

-((2(3a+9)+2))*7(21a+14)+21a(2+1=0



We calculate terms in parentheses: -((2(3a+9)+2))*7(21a+14), so:

(2(3a+9)+2))*7(21a+14





We calculate terms in parentheses: -((2(3a+9)+2))*7(21a+14), so:

(2(3a+9)+2))*7(21a+14





We calculate terms in parentheses: -((2(3a+9)+2))*7(21a+14), so:

(2(3a+9)+2))*7(21a+14





We calculate terms in parentheses: -((2(3a+9)+2))*7(21a+14), so:

(2(3a+9)+2))*7(21a+14





We calculate terms in parentheses: -((2(3a+9)+2))*7(21a+14), so:

(2(3a+9)+2))*7(21a+14





We calculate terms in parentheses: -((2(3a+9)+2))*7(21a+14), so:

(2(3a+9)+2))*7(21a+14





We calculate terms in parentheses: -((2(3a+9)+2))*7(21a+14), so:

(2(3a+9)+2))*7(21a+14





We calculate terms in parentheses: -((2(3a+9)+2))*7(21a+14), so:

(2(3a+9)+2))*7(21a+14





We calculate terms in parentheses: -((2(3a+9)+2))*7(21a+14), so:

(2(3a+9)+2))*7(21a+14





We calculate terms in parentheses: -((2(3a+9)+2))*7(21a+14), so:

(2(3a+9)+2))*7(21a+14





We calculate terms in parentheses: -((2(3a+9)+2))*7(21a+14), so:

(2(3a+9)+2))*7(21a+14





We calculate terms in parentheses: -((2(3a+9)+2))*7(21a+14), so:

(2(3a+9)+2))*7(21a+14





We calculate terms in parentheses: -((2(3a+9)+2))*7(21a+14), so:

(2(3a+9)+2))*7(21a+14





We calculate terms in parentheses: -((2(3a+9)+2))*7(21a+14), so:

(2(3a+9)+2))*7(21a+14





We calculate terms in parentheses: -((2(3a+9)+2))*7(21a+14), so:

(2(3a+9)+2))*7(21a+14





We calculate terms in parentheses: -((2(3a+9)+2))*7(21a+14), so:

(2(3a+9)+2))*7(21a+14





We calculate terms in parentheses: -((2(3a+9)+2))*7(21a+14), so:

(2(3a+9)+2))*7(21a+14





We calculate terms in parentheses: -((2(3a+9)+2))*7(21a+14), so:

(2(3a+9)+2))*7(21a+14





We calculate terms in parentheses: -((2(3a+9)+2))*7(21a+14), so:

(2(3a+9)+2))*7(21a+14





We calculate terms in parentheses: -((2(3a+9)+2))*7(21a+14), so:

(2(3a+9)+2))*7(21a+14





We calculate terms in parentheses: -((2(3a+9)+2))*7(21a+14), so:

(2(3a+9)+2))*7(21a+14





We calculate terms in parentheses: -((2(3a+9)+2))*7(21a+14), so:

(2(3a+9)+2))*7(21a+14





We calculate terms in parentheses: -((2(3a+9)+2))*7(21a+14), so:

(2(3a+9)+2))*7(21a+14





We calculate terms in parentheses: -((2(3a+9)+2))*7(21a+14), so:

(2(3a+9)+2))*7(21a+14





We calculate terms in parentheses: -((2(3a+9)+2))*7(21a+14), so:

(2(3a+9)+2))*7(21a+14





We calculate terms in parentheses: -((2(3a+9)+2))*7(21a+14), so:

(2(3a+9)+2))*7(21a+14





We calculate terms in parentheses: -((2(3a+9)+2))*7(21a+14), so:

(2(3a+9)+2))*7(21a+14





We calculate terms in parentheses: -((2(3a+9)+2))*7(21a+14), so:

(2(3a+9)+2))*7(21a+14





We calculate terms in parentheses: -((2(3a+9)+2))*7(21a+14), so:

(2(3a+9)+2))*7(21a+14





We calculate terms in parentheses: -((2(3a+9)+2))*7(21a+14), so:

(2(3a+9)+2))*7(21a+14





We calculate terms in parentheses: -((2(3a+9)+2))*7(21a+14), so:

(2(3a+9)+2))*7(21a+14





We calculate terms in parentheses: -((2(3a+9)+2))*7(21a+14), so:

(2(3a+9)+2))*7(21a+14





We calculate terms in parentheses: -((2(3a+9)+2))*7(21a+14), so:

(2(3a+9)+2))*7(21a+14





We calculate terms in parentheses: -((2(3a+9)+2))*7(21a+14), so:

(2(3a+9)+2))*7(21a+14





We calculate terms in parentheses: -((2(3a+9)+2))*7(21a+14), so:

(2(3a+9)+2))*7(21a+14





We calculate terms in parentheses: -((2(3a+9)+2))*7(21a+14), so:

(2(3a+9)+2))*7(21a+14





We calculate terms in parentheses: -((2(3a+9)+2))*7(21a+14), so:

(2(3a+9)+2))*7(21a+14





We calculate terms in parentheses: -((2(3a+9)+2))*7(21a+14), so:

(2(3a+9)+2))*7(21a+14





We calculate terms in parentheses: -((2(3a+9)+2))*7(21a+14), so:

(2(3a+9)+2))*7(21a+14





We calculate terms in parentheses: -((2(3a+9)+2))*7(2

See similar equations:

| 1/t=3/12 | | 40=4+9x | | 2x-6=20*2 | | 1=-2u+1 | | 2(x+8)=39 | | –6−s=–s−6 | | -1=-s+1 | | 3x+57=290 | | (2x-4)/2=24 | | 7*1.5^x=2*5^(-0.5x) | | 4=h-5h | | B(x)=50.00-0.09x | | (2x+6)/2=20 | | X=-150y=-15 | | -2(5+6c)+16=-9- | | |3x-4|=11 | | 0.8(x2.5)=6 | | 20x-12=10x+68 | | 10x=180+5x | | 25=(v/5)+8 | | (4k−10)/(k)=8 | | 10+4n=26 | | Y=20x+27 | | 2x+31+5x+3=90 | | -x/7=18 | | 3=c4−1 | | -4.8(x+1.5)=-7.2(1+2.3x) | | m^2=-6m+6 | | 12/5x−2/3=2/5x−2 | | 5(x-4)-3(x-2)=2(x-8) | | 0=–6t+6t | | (6b+10/4)=7 |

Equations solver categories