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3+12/5x=2+1/4x-1
We move all terms to the left:
3+12/5x-(2+1/4x-1)=0
Domain of the equation: 5x!=0
x!=0/5
x!=0
x∈R
Domain of the equation: 4x-1)!=0We add all the numbers together, and all the variables
x∈R
12/5x-(1/4x+1)+3=0
We get rid of parentheses
12/5x-1/4x-1+3=0
We calculate fractions
48x/20x^2+(-5x)/20x^2-1+3=0
We add all the numbers together, and all the variables
48x/20x^2+(-5x)/20x^2+2=0
We multiply all the terms by the denominator
48x+(-5x)+2*20x^2=0
Wy multiply elements
40x^2+48x+(-5x)=0
We get rid of parentheses
40x^2+48x-5x=0
We add all the numbers together, and all the variables
40x^2+43x=0
a = 40; b = 43; c = 0;
Δ = b2-4ac
Δ = 432-4·40·0
Δ = 1849
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1849}=43$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(43)-43}{2*40}=\frac{-86}{80} =-1+3/40 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(43)+43}{2*40}=\frac{0}{80} =0 $
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