3+17=13x2

Solution for 3+17=13x2 equation:

3+17=13x^2

We move all terms to the left:

3+17-(13x^2)=0

We add all the numbers together, and all the variables

-13x^2+20=0

a = -13; b = 0; c = +20;
Δ = b2-4ac
Δ = 02-4·(-13)·20
Δ = 1040
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1040}=\sqrt{16*65}=\sqrt{16}*\sqrt{65}=4\sqrt{65}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4\sqrt{65}}{2*-13}=\frac{0-4\sqrt{65}}{-26}
=-\frac{4\sqrt{65}}{-26}
=-\frac{2\sqrt{65}}{-13}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4\sqrt{65}}{2*-13}=\frac{0+4\sqrt{65}}{-26}
=\frac{4\sqrt{65}}{-26}
=\frac{2\sqrt{65}}{-13}
$