3+2(-4-2b)=-3(b-1)

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Solution for 3+2(-4-2b)=-3(b-1) equation: 



3+2(-4-2b)=-3(b-1)

We move all terms to the left:

3+2(-4-2b)-(-3(b-1))=0

We add all the numbers together, and all the variables

2(-2b-4)-(-3(b-1))+3=0

We multiply parentheses

-4b-(-3(b-1))-8+3=0



We calculate terms in parentheses: -(-3(b-1)), so:

-3(b-1)

We multiply parentheses

-3b+3

Back to the equation:

-(-3b+3)



We add all the numbers together, and all the variables

-4b-(-3b+3)-5=0

We get rid of parentheses

-4b+3b-3-5=0

We add all the numbers together, and all the variables

-1b-8=0

We move all terms containing b to the left, all other terms to the right

-b=8

b=8/-1

b=-8

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