3+2(3b-4)=5(b-1)-2

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Solution for 3+2(3b-4)=5(b-1)-2 equation: 



3+2(3b-4)=5(b-1)-2

We move all terms to the left:

3+2(3b-4)-(5(b-1)-2)=0

We multiply parentheses

6b-(5(b-1)-2)-8+3=0



We calculate terms in parentheses: -(5(b-1)-2), so:

5(b-1)-2

We multiply parentheses

5b-5-2

We add all the numbers together, and all the variables

5b-7

Back to the equation:

-(5b-7)



We add all the numbers together, and all the variables

6b-(5b-7)-5=0

We get rid of parentheses

6b-5b+7-5=0

We add all the numbers together, and all the variables

b+2=0

We move all terms containing b to the left, all other terms to the right

b=-2

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