3+2(m+3)=2(2m+1)

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Solution for 3+2(m+3)=2(2m+1) equation: 



3+2(m+3)=2(2m+1)

We move all terms to the left:

3+2(m+3)-(2(2m+1))=0

We multiply parentheses

2m-(2(2m+1))+6+3=0



We calculate terms in parentheses: -(2(2m+1)), so:

2(2m+1)

We multiply parentheses

4m+2

Back to the equation:

-(4m+2)



We add all the numbers together, and all the variables

2m-(4m+2)+9=0

We get rid of parentheses

2m-4m-2+9=0

We add all the numbers together, and all the variables

-2m+7=0

We move all terms containing m to the left, all other terms to the right

-2m=-7

m=-7/-2

m=3+1/2

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