3+2(m+3)=2(2m+1)

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Solution for 3+2(m+3)=2(2m+1) equation:



3+2(m+3)=2(2m+1)
We move all terms to the left:
3+2(m+3)-(2(2m+1))=0
We multiply parentheses
2m-(2(2m+1))+6+3=0
We calculate terms in parentheses: -(2(2m+1)), so:
2(2m+1)
We multiply parentheses
4m+2
Back to the equation:
-(4m+2)
We add all the numbers together, and all the variables
2m-(4m+2)+9=0
We get rid of parentheses
2m-4m-2+9=0
We add all the numbers together, and all the variables
-2m+7=0
We move all terms containing m to the left, all other terms to the right
-2m=-7
m=-7/-2
m=3+1/2

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