3+2(x+1)=3(x-1)

Solution for 3+2(x+1)=3(x-1) equation:

3+2(x+1)=3(x-1)

We move all terms to the left:

3+2(x+1)-(3(x-1))=0

We multiply parentheses

2x-(3(x-1))+2+3=0


We calculate terms in parentheses: -(3(x-1)), so:

3(x-1)

We multiply parentheses

3x-3

Back to the equation:

-(3x-3)


We add all the numbers together, and all the variables

2x-(3x-3)+5=0

We get rid of parentheses

2x-3x+3+5=0

We add all the numbers together, and all the variables

-1x+8=0

We move all terms containing x to the left, all other terms to the right

-x=-8

x=-8/-1

x=+8