3+2(x+1)=4-3(x+2)

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Solution for 3+2(x+1)=4-3(x+2) equation:



3+2(x+1)=4-3(x+2)
We move all terms to the left:
3+2(x+1)-(4-3(x+2))=0
We multiply parentheses
2x-(4-3(x+2))+2+3=0
We calculate terms in parentheses: -(4-3(x+2)), so:
4-3(x+2)
determiningTheFunctionDomain -3(x+2)+4
We multiply parentheses
-3x-6+4
We add all the numbers together, and all the variables
-3x-2
Back to the equation:
-(-3x-2)
We add all the numbers together, and all the variables
2x-(-3x-2)+5=0
We get rid of parentheses
2x+3x+2+5=0
We add all the numbers together, and all the variables
5x+7=0
We move all terms containing x to the left, all other terms to the right
5x=-7
x=-7/5
x=-1+2/5

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