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3+2(x+3)=9x-3
We move all terms to the left:
3+2(x+3)-(9x-3)=0
We multiply parentheses
2x-(9x-3)+6+3=0
We get rid of parentheses
2x-9x+3+6+3=0
We add all the numbers together, and all the variables
-7x+12=0
We move all terms containing x to the left, all other terms to the right
-7x=-12
x=-12/-7
x=1+5/7
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