3+2(x+4)=2x-10(x+1)

Solution for 3+2(x+4)=2x-10(x+1) equation:

3+2(x+4)=2x-10(x+1)

We move all terms to the left:

3+2(x+4)-(2x-10(x+1))=0

We multiply parentheses

2x-(2x-10(x+1))+8+3=0


We calculate terms in parentheses: -(2x-10(x+1)), so:

2x-10(x+1)

We multiply parentheses

2x-10x-10

We add all the numbers together, and all the variables

-8x-10

Back to the equation:

-(-8x-10)


We add all the numbers together, and all the variables

2x-(-8x-10)+11=0

We get rid of parentheses

2x+8x+10+11=0

We add all the numbers together, and all the variables

10x+21=0

We move all terms containing x to the left, all other terms to the right

10x=-21

x=-21/10

x=-2+1/10