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3+2(x+4)=4x-2/5(5x-5)
We move all terms to the left:
3+2(x+4)-(4x-2/5(5x-5))=0
Domain of the equation: 5(5x-5))!=0We multiply parentheses
x∈R
2x-(4x-2/5(5x-5))+8+3=0
We multiply all the terms by the denominator
2x*5(5x-5))-(4x+8*5(5x-5))+3*5(5x-2-5))=0
We add all the numbers together, and all the variables
2x*5(5x-5))-(4x+8*5(5x-5))+3*5(5x-7))=0
We add all the numbers together, and all the variables
2x*5(5x-5))-(4x+8*5(5x-5))+3*5(5x=0
Wy multiply elements
10x^2(5+200x^2(5=0
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