3+20f=9f+12f+19

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Solution for 3+20f=9f+12f+19 equation: 



3+20f=9f+12f+19

We move all terms to the left:

3+20f-(9f+12f+19)=0

We add all the numbers together, and all the variables

20f-(21f+19)+3=0

We get rid of parentheses

20f-21f-19+3=0

We add all the numbers together, and all the variables

-1f-16=0

We move all terms containing f to the left, all other terms to the right

-f=16

f=16/-1

f=-16

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