3+20y=y+19+20y

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Solution for 3+20y=y+19+20y equation: 



3+20y=y+19+20y

We move all terms to the left:

3+20y-(y+19+20y)=0

We add all the numbers together, and all the variables

20y-(21y+19)+3=0

We get rid of parentheses

20y-21y-19+3=0

We add all the numbers together, and all the variables

-1y-16=0

We move all terms containing y to the left, all other terms to the right

-y=16

y=16/-1

y=-16

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