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3+2=x2-4
We move all terms to the left:
3+2-(x2-4)=0
We add all the numbers together, and all the variables
-(+x^2-4)+3+2=0
We add all the numbers together, and all the variables
-(+x^2-4)+5=0
We get rid of parentheses
-x^2+4+5=0
We add all the numbers together, and all the variables
-1x^2+9=0
a = -1; b = 0; c = +9;
Δ = b2-4ac
Δ = 02-4·(-1)·9
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{36}=6$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-6}{2*-1}=\frac{-6}{-2} =+3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+6}{2*-1}=\frac{6}{-2} =-3 $
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