3+2c=2(2+c)

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Solution for 3+2c=2(2+c) equation: 



3+2c=2(2+c)

We move all terms to the left:

3+2c-(2(2+c))=0

We add all the numbers together, and all the variables

2c-(2(c+2))+3=0



We calculate terms in parentheses: -(2(c+2)), so:

2(c+2)

We multiply parentheses

2c+4

Back to the equation:

-(2c+4)



We get rid of parentheses

2c-2c-4+3=0

We add all the numbers together, and all the variables

-1!=0

There is no solution for this equation

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