3+2d=12/3+2d=12

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Solution for 3+2d=12/3+2d=12 equation: 



3+2d=12/3+2d=12

We move all terms to the left:

3+2d-(12/3+2d)=0



Domain of the equation: 3+2d)!=0

We move all terms containing d to the left, all other terms to the right

2d)!=-3

d!=-3/1

d!=-3

d∈R



We add all the numbers together, and all the variables

2d-(2d+4)+3=0

We get rid of parentheses

2d-2d-4+3=0

We add all the numbers together, and all the variables

-1!=0

There is no solution for this equation

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