3+2x(4x-5)=9

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Solution for 3+2x(4x-5)=9 equation:



3+2x(4x-5)=9
We move all terms to the left:
3+2x(4x-5)-(9)=0
We add all the numbers together, and all the variables
2x(4x-5)-6=0
We multiply parentheses
8x^2-10x-6=0
a = 8; b = -10; c = -6;
Δ = b2-4ac
Δ = -102-4·8·(-6)
Δ = 292
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{292}=\sqrt{4*73}=\sqrt{4}*\sqrt{73}=2\sqrt{73}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-10)-2\sqrt{73}}{2*8}=\frac{10-2\sqrt{73}}{16} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-10)+2\sqrt{73}}{2*8}=\frac{10+2\sqrt{73}}{16} $

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