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3+2x+3=-(x+4)+3x-2
We move all terms to the left:
3+2x+3-(-(x+4)+3x-2)=0
We add all the numbers together, and all the variables
2x-(-(x+4)+3x-2)+6=0
We calculate terms in parentheses: -(-(x+4)+3x-2), so:We get rid of parentheses
-(x+4)+3x-2
We add all the numbers together, and all the variables
3x-(x+4)-2
We get rid of parentheses
3x-x-4-2
We add all the numbers together, and all the variables
2x-6
Back to the equation:
-(2x-6)
2x-2x+6+6=0
We add all the numbers together, and all the variables
12!=0
There is no solution for this equation
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