3+2x=2(2x+2)-3(x-4)

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Solution for 3+2x=2(2x+2)-3(x-4) equation: 



3+2x=2(2x+2)-3(x-4)

We move all terms to the left:

3+2x-(2(2x+2)-3(x-4))=0



We calculate terms in parentheses: -(2(2x+2)-3(x-4)), so:

2(2x+2)-3(x-4)

We multiply parentheses

4x-3x+4+12

We add all the numbers together, and all the variables

x+16

Back to the equation:

-(x+16)



We get rid of parentheses

2x-x-16+3=0

We add all the numbers together, and all the variables

x-13=0

We move all terms containing x to the left, all other terms to the right

x=13

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