3+2x=4(x+3)-3(x-2)

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Solution for 3+2x=4(x+3)-3(x-2) equation: 



3+2x=4(x+3)-3(x-2)

We move all terms to the left:

3+2x-(4(x+3)-3(x-2))=0



We calculate terms in parentheses: -(4(x+3)-3(x-2)), so:

4(x+3)-3(x-2)

We multiply parentheses

4x-3x+12+6

We add all the numbers together, and all the variables

x+18

Back to the equation:

-(x+18)



We get rid of parentheses

2x-x-18+3=0

We add all the numbers together, and all the variables

x-15=0

We move all terms containing x to the left, all other terms to the right

x=15

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