3+3(2-3k)=6(1-2k)

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Solution for 3+3(2-3k)=6(1-2k) equation: 



3+3(2-3k)=6(1-2k)

We move all terms to the left:

3+3(2-3k)-(6(1-2k))=0

We add all the numbers together, and all the variables

3(-3k+2)-(6(-2k+1))+3=0

We multiply parentheses

-9k-(6(-2k+1))+6+3=0



We calculate terms in parentheses: -(6(-2k+1)), so:

6(-2k+1)

We multiply parentheses

-12k+6

Back to the equation:

-(-12k+6)



We add all the numbers together, and all the variables

-9k-(-12k+6)+9=0

We get rid of parentheses

-9k+12k-6+9=0

We add all the numbers together, and all the variables

3k+3=0

We move all terms containing k to the left, all other terms to the right

3k=-3

k=-3/3

k=-1

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