3+3(2y-4)=-3(5y-1)+3

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Solution for 3+3(2y-4)=-3(5y-1)+3 equation: 



3+3(2y-4)=-3(5y-1)+3

We move all terms to the left:

3+3(2y-4)-(-3(5y-1)+3)=0

We multiply parentheses

6y-(-3(5y-1)+3)-12+3=0



We calculate terms in parentheses: -(-3(5y-1)+3), so:

-3(5y-1)+3

We multiply parentheses

-15y+3+3

We add all the numbers together, and all the variables

-15y+6

Back to the equation:

-(-15y+6)



We add all the numbers together, and all the variables

6y-(-15y+6)-9=0

We get rid of parentheses

6y+15y-6-9=0

We add all the numbers together, and all the variables

21y-15=0

We move all terms containing y to the left, all other terms to the right

21y=15

y=15/21

y=5/7

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