3+3(3b+2)=36

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Solution for 3+3(3b+2)=36 equation: 



3+3(3b+2)=36

We move all terms to the left:

3+3(3b+2)-(36)=0

We add all the numbers together, and all the variables

3(3b+2)-33=0

We multiply parentheses

9b+6-33=0

We add all the numbers together, and all the variables

9b-27=0

We move all terms containing b to the left, all other terms to the right

9b=27

b=27/9

b=3

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