3+3(5y-3)=-2(4y-1)+7y

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Solution for 3+3(5y-3)=-2(4y-1)+7y equation: 



3+3(5y-3)=-2(4y-1)+7y

We move all terms to the left:

3+3(5y-3)-(-2(4y-1)+7y)=0

We multiply parentheses

15y-(-2(4y-1)+7y)-9+3=0



We calculate terms in parentheses: -(-2(4y-1)+7y), so:

-2(4y-1)+7y

We add all the numbers together, and all the variables

7y-2(4y-1)

We multiply parentheses

7y-8y+2

We add all the numbers together, and all the variables

-1y+2

Back to the equation:

-(-1y+2)



We add all the numbers together, and all the variables

15y-(-1y+2)-6=0

We get rid of parentheses

15y+1y-2-6=0

We add all the numbers together, and all the variables

16y-8=0

We move all terms containing y to the left, all other terms to the right

16y=8

y=8/16

y=1/2

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