3+3(k+3)=6(k-2)+12

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Solution for 3+3(k+3)=6(k-2)+12 equation:


3+3(k+3)=6(k-2)+12

We simplify the equation to the form, which is simple to understand 
3+3(k+3)=6(k-2)+12

Reorder the terms in parentheses
3+(+3k+9)=6*(k-2)+12

Remove unnecessary parentheses
+3+3k+9=+6+*(+k-2+)+12

Reorder the terms in parentheses
3+3k+9=+(+6k-12)+12

Remove unnecessary parentheses
+3+3k+9=+6k-12+12

We move all terms containing k to the left and all other terms to the right. 
+3k-6k=-12+12-3-9

We simplify left and right side of the equation. 
-3k=-12

We divide both sides of the equation by -3 to get k. 
k=4

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