3+3(x+3)=6(x-2)+9

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Solution for 3+3(x+3)=6(x-2)+9 equation: 



3+3(x+3)=6(x-2)+9

We move all terms to the left:

3+3(x+3)-(6(x-2)+9)=0

We multiply parentheses

3x-(6(x-2)+9)+9+3=0



We calculate terms in parentheses: -(6(x-2)+9), so:

6(x-2)+9

We multiply parentheses

6x-12+9

We add all the numbers together, and all the variables

6x-3

Back to the equation:

-(6x-3)



We add all the numbers together, and all the variables

3x-(6x-3)+12=0

We get rid of parentheses

3x-6x+3+12=0

We add all the numbers together, and all the variables

-3x+15=0

We move all terms containing x to the left, all other terms to the right

-3x=-15

x=-15/-3

x=+5

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