3+3/2x+4=3x-5/2x

Solution for 3+3/2x+4=3x-5/2x equation:

3+3/2x+4=3x-5/2x

We move all terms to the left:

3+3/2x+4-(3x-5/2x)=0


Domain of the equation: 2x!=0

x!=0/2

x!=0

x∈R



Domain of the equation: 2x)!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

3/2x-(+3x-5/2x)+3+4=0

We add all the numbers together, and all the variables

3/2x-(+3x-5/2x)+7=0

We get rid of parentheses

3/2x-3x+5/2x+7=0

We multiply all the terms by the denominator


-3x*2x+7*2x+3+5=0

We add all the numbers together, and all the variables

-3x*2x+7*2x+8=0

Wy multiply elements

-6x^2+14x+8=0

a = -6; b = 14; c = +8;
Δ = b2-4ac
Δ = 142-4·(-6)·8
Δ = 388
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{388}=\sqrt{4*97}=\sqrt{4}*\sqrt{97}=2\sqrt{97}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(14)-2\sqrt{97}}{2*-6}=\frac{-14-2\sqrt{97}}{-12}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(14)+2\sqrt{97}}{2*-6}=\frac{-14+2\sqrt{97}}{-12}
$