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3+3/2x+4=4x+4x-5/2x
We move all terms to the left:
3+3/2x+4-(4x+4x-5/2x)=0
Domain of the equation: 2x!=0
x!=0/2
x!=0
x∈R
Domain of the equation: 2x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
3/2x-(+8x-5/2x)+3+4=0
We add all the numbers together, and all the variables
3/2x-(+8x-5/2x)+7=0
We get rid of parentheses
3/2x-8x+5/2x+7=0
We multiply all the terms by the denominator
-8x*2x+7*2x+3+5=0
We add all the numbers together, and all the variables
-8x*2x+7*2x+8=0
Wy multiply elements
-16x^2+14x+8=0
a = -16; b = 14; c = +8;
Δ = b2-4ac
Δ = 142-4·(-16)·8
Δ = 708
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{708}=\sqrt{4*177}=\sqrt{4}*\sqrt{177}=2\sqrt{177}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(14)-2\sqrt{177}}{2*-16}=\frac{-14-2\sqrt{177}}{-32} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(14)+2\sqrt{177}}{2*-16}=\frac{-14+2\sqrt{177}}{-32} $
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