3+3/2x+4=4x-1/2x

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Solution for 3+3/2x+4=4x-1/2x equation:



3+3/2x+4=4x-1/2x
We move all terms to the left:
3+3/2x+4-(4x-1/2x)=0
Domain of the equation: 2x!=0
x!=0/2
x!=0
x∈R
Domain of the equation: 2x)!=0
x!=0/1
x!=0
x∈R
We add all the numbers together, and all the variables
3/2x-(+4x-1/2x)+3+4=0
We add all the numbers together, and all the variables
3/2x-(+4x-1/2x)+7=0
We get rid of parentheses
3/2x-4x+1/2x+7=0
We multiply all the terms by the denominator
-4x*2x+7*2x+3+1=0
We add all the numbers together, and all the variables
-4x*2x+7*2x+4=0
Wy multiply elements
-8x^2+14x+4=0
a = -8; b = 14; c = +4;
Δ = b2-4ac
Δ = 142-4·(-8)·4
Δ = 324
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{324}=18$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(14)-18}{2*-8}=\frac{-32}{-16} =+2 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(14)+18}{2*-8}=\frac{4}{-16} =-1/4 $

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