3+3x=2(-x+6)-19

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Solution for 3+3x=2(-x+6)-19 equation:



3+3x=2(-x+6)-19
We move all terms to the left:
3+3x-(2(-x+6)-19)=0
We add all the numbers together, and all the variables
3x-(2(-1x+6)-19)+3=0
We calculate terms in parentheses: -(2(-1x+6)-19), so:
2(-1x+6)-19
We multiply parentheses
-2x+12-19
We add all the numbers together, and all the variables
-2x-7
Back to the equation:
-(-2x-7)
We get rid of parentheses
3x+2x+7+3=0
We add all the numbers together, and all the variables
5x+10=0
We move all terms containing x to the left, all other terms to the right
5x=-10
x=-10/5
x=-2

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