3+3x=2(-x+6)-19

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Solution for 3+3x=2(-x+6)-19 equation: 



3+3x=2(-x+6)-19

We move all terms to the left:

3+3x-(2(-x+6)-19)=0

We add all the numbers together, and all the variables

3x-(2(-1x+6)-19)+3=0



We calculate terms in parentheses: -(2(-1x+6)-19), so:

2(-1x+6)-19

We multiply parentheses

-2x+12-19

We add all the numbers together, and all the variables

-2x-7

Back to the equation:

-(-2x-7)



We get rid of parentheses

3x+2x+7+3=0

We add all the numbers together, and all the variables

5x+10=0

We move all terms containing x to the left, all other terms to the right

5x=-10

x=-10/5

x=-2

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