3+3y+4y+10=48

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Solution for 3+3y+4y+10=48 equation: 



3+3y+4y+10=48

We move all terms to the left:

3+3y+4y+10-(48)=0

We add all the numbers together, and all the variables

7y-35=0

We move all terms containing y to the left, all other terms to the right

7y=35

y=35/7

y=5

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