3+4(2x+3)=2-8(3x-2)

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Solution for 3+4(2x+3)=2-8(3x-2) equation: 



3+4(2x+3)=2-8(3x-2)

We move all terms to the left:

3+4(2x+3)-(2-8(3x-2))=0

We multiply parentheses

8x-(2-8(3x-2))+12+3=0



We calculate terms in parentheses: -(2-8(3x-2)), so:

2-8(3x-2)

determiningTheFunctionDomain
-8(3x-2)+2

We multiply parentheses

-24x+16+2

We add all the numbers together, and all the variables

-24x+18

Back to the equation:

-(-24x+18)



We add all the numbers together, and all the variables

8x-(-24x+18)+15=0

We get rid of parentheses

8x+24x-18+15=0

We add all the numbers together, and all the variables

32x-3=0

We move all terms containing x to the left, all other terms to the right

32x=3

x=3/32

x=3/32

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