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3+4(5x-6)=5-5(2x+1)
We move all terms to the left:
3+4(5x-6)-(5-5(2x+1))=0
We multiply parentheses
20x-(5-5(2x+1))-24+3=0
We calculate terms in parentheses: -(5-5(2x+1)), so:We add all the numbers together, and all the variables
5-5(2x+1)
determiningTheFunctionDomain -5(2x+1)+5
We multiply parentheses
-10x-5+5
We add all the numbers together, and all the variables
-10x
Back to the equation:
-(-10x)
20x-(-10x)-21=0
We get rid of parentheses
20x+10x-21=0
We add all the numbers together, and all the variables
30x-21=0
We move all terms containing x to the left, all other terms to the right
30x=21
x=21/30
x=7/10
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