3+4(n-2)=2n+3(n+4)

Solution for 3+4(n-2)=2n+3(n+4) equation:

3+4(n-2)=2n+3(n+4)

We move all terms to the left:

3+4(n-2)-(2n+3(n+4))=0

We multiply parentheses

4n-(2n+3(n+4))-8+3=0


We calculate terms in parentheses: -(2n+3(n+4)), so:

2n+3(n+4)

We multiply parentheses

2n+3n+12

We add all the numbers together, and all the variables

5n+12

Back to the equation:

-(5n+12)


We add all the numbers together, and all the variables

4n-(5n+12)-5=0

We get rid of parentheses

4n-5n-12-5=0

We add all the numbers together, and all the variables

-1n-17=0

We move all terms containing n to the left, all other terms to the right

-n=17

n=17/-1

n=-17