3+4=(19+x)/2

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Solution for 3+4=(19+x)/2 equation: 



3+4=(19+x)/2

We move all terms to the left:

3+4-((19+x)/2)=0

We add all the numbers together, and all the variables

-((x+19)/2)+3+4=0

We add all the numbers together, and all the variables

-((x+19)/2)+7=0

We multiply all the terms by the denominator


-((x+19)+7*2)=0



We calculate terms in parentheses: -((x+19)+7*2), so:

(x+19)+7*2

We add all the numbers together, and all the variables

(x+19)+14

We get rid of parentheses

x+19+14

We add all the numbers together, and all the variables

x+33

Back to the equation:

-(x+33)



We get rid of parentheses

-x-33=0

We add all the numbers together, and all the variables

-1x-33=0

We move all terms containing x to the left, all other terms to the right

-x=33

x=33/-1

x=-33

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